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let the natural number n have the decimal numeral 123,480,38d, where d …

Question

let the natural number n have the decimal numeral 123,480,38d, where d is the units digit. use divisibility tests to give all of the choices of d by which n is divisible. complete parts (c) through (h) below.

(c) for what value(s) of d is n divisible by 4?
(use a comma to separate answers as needed.)

(d) for what value(s) of d is n divisible by 5?
(use a comma to separate answers as needed.)

(e) for what value(s) of d is n divisible by 6?
(use a comma to separate answers as needed.)

(f) for what value(s) of d is n divisible by 8?
(use a comma to separate answers as needed.)

(g) for what value(s) of d is n divisible by 9?
(use a comma to separate answers as needed.)

(h) for what value(s) of d is n divisible by 10?
(use a comma to separate answers as needed.)

Explanation:

Analyze the number and divisibility rules

Using the Divisibility Rules knowledge point
The natural number is \(n = 123,480,38d\), where \(d \in \{0, 1, 2, 3, 4, 5, 6, 7, 8, 9\}\).
We need to determine the values of \(d\) for which \(n\) is divisible by \(4\), \(5\), \(6\), \(9\), \(3\), and \(10\).

Divisibility by 4 and 5

Using the Divisibility Rules knowledge point

  • For divisibility by \(4\), the last two digits \(8d\) must form a number divisible by \(4\).

Since \(80, 84, 88\) are divisible by \(4\), we have \(d \in \{0, 4, 8\}\).

  • For divisibility by \(5\), the units digit \(d\) must be \(0\) or \(5\).

Thus, \(d \in \{0, 5\}\).

Divisibility by 6 and 9

Using the Divisibility Rules knowledge point

  • For divisibility by \(9\), the sum of the digits must be divisible by \(9\).

Sum of digits: \(1 + 2 + 3 + 4 + 8 + 0 + 3 + 8 + d = 29 + d\).
For \(29 + d\) to be divisible by \(9\), we need \(29 + d = 36 \implies d = 7\).

  • For divisibility by \(6\), \(n\) must be divisible by both \(2\) and \(3\).
  • Divisibility by \(2\) requires \(d \in \{0, 2, 4, 6, 8\}\).
  • Divisibility by \(3\) requires the sum of digits \(29 + d\) to be divisible by \(3\).

Thus, \(29 + d \in \{30, 33, 36\} \implies d \in \{1, 4, 7\}\).

  • Intersecting these sets: \(d \in \{0, 2, 4, 6, 8\} \cap \{1, 4, 7\} = \{4\}\).

Divisibility by 3 and 10

Using the Divisibility Rules knowledge point

  • For divisibility by \(3\), the sum of digits \(29 + d\) must be divisible by \(3\).

Thus, \(d \in \{1, 4, 7\}\).

  • For divisibility by \(10\), the units digit \(d\) must be \(0\).

Thus, \(d = 0\).

Answer:

PartQuestionAnswer
(d)For what value(s) of \(d\) is \(n\) divisible by 5?0, 5
(e)For what value(s) of \(d\) is \(n\) divisible by 6?4
(f)For what value(s) of \(d\) is \(n\) divisible by 9?7
(g)For what value(s) of \(d\) is \(n\) divisible by 3?1, 4, 7
(h)For what value(s) of \(d\) is \(n\) divisible by 10?0