Question

lab data
triglyceride molecular formula
$c_{51}h_{98}o_{6}$
triglyceride molar mass (g/mol)
807.29
mass of triglyceride (g)
4.13
soap name
sodium palmitate
soap molecular formula
$nac_{16}h_{31}o_{2}$
soap molar mass (g/mol)
278.40
mass of filter paper (g)
0.23
mass of filter paper + soap (g)
3.56
mass of soap (g)
3.33
theoretical yield (g)
actual yield (g)
3.33
percent yield (%)
ph of soap solution
test
observations
ph reading
ph

Explanation:

Step1: Calculate moles of triglyceride

Moles of triglyceride = $\frac{\text{Mass of triglyceride}}{\text{Molar mass of triglyceride}}=\frac{4.13}{807.29}$ mol

Step2: Determine mole - ratio in saponification reaction

The saponification reaction of a triglyceride to form soap has a certain stoichiometry. For a triglyceride to form 3 moles of soap. Let's assume a 1:3 mole - ratio of triglyceride to soap for a typical saponification reaction.

Step3: Calculate theoretical moles of soap

Theoretical moles of soap = 3×(moles of triglyceride) = 3×$\frac{4.13}{807.29}$ mol

Step4: Calculate theoretical mass of soap

Theoretical yield (mass of soap) = Theoretical moles of soap×Molar mass of soap = 3×$\frac{4.13}{807.29}$×278.40 g
$=\frac{3\times4.13\times278.40}{807.29}\approx4.26$ g

Answer:

4.26