Question

kuta software - infinite pre - algebra
evaluating variable expressions
evaluate each using the values given.

1. $n^2 - m$; use $m = 7$, and $n = 8$
2. $8(x - y)$; use $x = 5$, and $y = 2$
3. $yx\div2$; use $x = 7$, and $y = 2$
4. $m - n\div4$; use $m = 5$, and $n = 8$
5. $x - y + 6$; use $x = 6$, and $y = 1$
6. $z + x^3$; use $x = 1$, and $z = 19$
7. $y + yx$; use $x = 15$, and $y = 8$
8. $q\div6 + p$; use $p = 10$, and $q = 12$
9. $x + 8 - y$; use $x = 20$, and $y = 17$
10. $15 - (m + p)$; use $m = 3$, and $p = 10$
11. $10 - x + y\div2$; use $x = 5$, and $y = 2$
12. $p - 2 + qp$; use $p = 7$, and $q = 4$

Explanation:

Problem 1: \( n^2 - m \); use \( m = 7 \), and \( n = 8 \)

Step1: Substitute values

Substitute \( m = 7 \) and \( n = 8 \) into the expression: \( 8^2 - 7 \)

Step2: Calculate exponent

Calculate \( 8^2 = 64 \)

Step3: Subtract

Subtract 7 from 64: \( 64 - 7 = 57 \)

Step1: Substitute values

Substitute \( x = 5 \) and \( y = 2 \) into the expression: \( 8(5 - 2) \)

Step2: Calculate inside parentheses

Calculate \( 5 - 2 = 3 \)

Step3: Multiply

Multiply 8 by 3: \( 8 \times 3 = 24 \)

Step1: Substitute values

Substitute \( x = 7 \) and \( y = 2 \) into the expression: \( 2 \times 7 \div 2 \)

Step2: Multiply

Calculate \( 2 \times 7 = 14 \)

Step3: Divide

Divide 14 by 2: \( 14 \div 2 = 7 \)

Answer:

57

Problem 2: \( 8(x - y) \); use \( x = 5 \), and \( y = 2 \)