Question

a 4.5 kg textbook is sitting on a table 0.8 meters above the ground. how much gravitational potential energy does the textbook have? remember : $e_g = mgh$ $g = 10 \frac{m}{s^2}$ $e_g = ? j$

Explanation:

Step1: Identify the values

We have \( m = 4.5\space kg \), \( g = 10\space \frac{m}{s^2} \), and \( h = 0.8\space m \). The formula for gravitational potential energy is \( E_g = mgh \).

Step2: Substitute the values into the formula

Substitute \( m = 4.5 \), \( g = 10 \), and \( h = 0.8 \) into \( E_g = mgh \). So we get \( E_g = 4.5\times10\times0.8 \).

Step3: Calculate the result

First, calculate \( 4.5\times10 = 45 \), then \( 45\times0.8 = 36 \).

Answer:

36