Question

a 0.5 kg plate falls from a table. at 0.2 s, the velocity of the plate is 2.0 m/s. what is the kinetic energy of the plate?
$e_k = ?$ j
$e_k = \frac{1}{2}mv^2$
6 j
3 j
1 j

Explanation:

Step1: Identify given values

Mass \( m = 0.5 \, \text{kg} \), velocity \( v = 2.0 \, \text{m/s} \).

Step2: Apply kinetic energy formula

Use \( E_{K}=\frac{1}{2}mv^{2} \). Substitute \( m = 0.5 \) and \( v = 2.0 \):
\( E_{K}=\frac{1}{2} \times 0.5 \times (2.0)^{2} \)
First, calculate \( (2.0)^{2}=4.0 \). Then:
\( E_{K}=\frac{1}{2} \times 0.5 \times 4.0 \)
\( \frac{1}{2} \times 0.5 = 0.25 \), then \( 0.25 \times 4.0 = 1.0 \).

Answer:

1 J