Question

john called a plumber to fix a leak in his bathroom. the plumber charged:

• $50 to come to the house.
• $25 per hour to fix the leak.

if the total cost was $125, how many hours was the plumber at johns house?
○ 6 hours
○ 5 hours
○ 4 hours
○ 3 hours

Explanation:

Step1: Define variables

Let \( h \) be the number of hours the plumber worked. The total cost \( C \) is the sum of the fixed cost (\$50) and the hourly cost (\( 25h \)). So the equation is \( C = 50 + 25h \).

Step2: Substitute total cost

We know the total cost \( C = 125 \). Substitute into the equation: \( 125 = 50 + 25h \).

Step3: Solve for h

Subtract 50 from both sides: \( 125 - 50 = 25h \), which simplifies to \( 75 = 25h \). Then divide both sides by 25: \( h = \frac{75}{25} = 3 \).

Answer:

3 hours