Question

john called a plumber to fix a leak in his bathroom. the plumber charged: - $50 to come to the house. - $25 per hour to fix the leak. if the total cost was $125, how many hours was the plumber at johns house? 6 hours 5 hours 4 hours 3 hours

Explanation:

Step1: Define variables

Let \( h \) be the number of hours the plumber worked.

Step2: Set up the cost equation

The total cost is the sum of the fixed cost (\$50) and the variable cost (\$25 per hour times the number of hours). So the equation is \( 50 + 25h = 125 \).

Step3: Solve for \( h \)

Subtract 50 from both sides: \( 25h = 125 - 50 \), which simplifies to \( 25h = 75 \). Then divide both sides by 25: \( h=\frac{75}{25}=3 \)? Wait, no, wait. Wait, 125 - 50 is 75? Wait, no, 125 - 50 is 75? Wait, 50 + 25h = 125. Subtract 50: 25h = 75? Wait, no, 125 - 50 is 75? Wait, 50 + 25h = 125. So 25h = 125 - 50 = 75? Then h = 75 / 25 = 3? But wait, the options have 3 hours as an option? Wait, but let's check again. Wait, 50 + 25*3 = 50 +75 = 125? Yes! Wait, 50 +75 is 125. So the plumber worked 3 hours? Wait, but let's re - do the steps.

Wait, initial cost: \$50 to come. Then \$25 per hour. Total cost \$125. So the cost for the hours is total cost minus the call - out fee: 125 - 50 = 75. Then number of hours is 75 divided by 25, which is 3. So h = 3.

Answer:

3 hours (the option with "3 hours")