Question

in △jkl, solve for x. 74.89 30.29 38.16 66.73

Explanation:

Step1: Use cosine function

In a right - triangle, $\cos\theta=\frac{\text{adjacent}}{\text{hypotenuse}}$. Here, $\theta = 27^{\circ}$, adjacent side $KL = 34$, and hypotenuse $JL=x$. So, $\cos(27^{\circ})=\frac{34}{x}$.

Step2: Solve for $x$

We can rewrite the equation as $x=\frac{34}{\cos(27^{\circ})}$. Since $\cos(27^{\circ})\approx0.8910$, then $x=\frac{34}{0.8910}\approx38.16$.

Answer:

38.16