Question

the iron in the compound has a charge of fe+2. what is the formula of iron(ii) chromate? chromate ion: (cro4)-2 fecro4 fe(cro4)2 fecr2o7 fe2cro4

Explanation:

Step1: Determine the charge balance

The iron ion has a charge of \(Fe^{+2}\), and the chromate ion has a charge of \((CrO_4)^{-2}\).

Step2: Write the formula

For the compound to be neutral, the sum of the charges of the ions must be zero. Since the charge of \(Fe^{+2}\) is \(+ 2\) and the charge of \((CrO_4)^{-2}\) is \(-2\), we need one \(Fe^{+2}\) ion and one \((CrO_4)^{-2}\) ion. So the formula is \(FeCrO_4\).

Answer:

\(FeCrO_4\)