6. ionic compounds
1. write the formula
(hint: must criss cross)
a) beryllium iodide
b) aluminum oxide
c) barium fluoride
2. write the name
a) k₂s
b) nai
c) li₂o
7. molecular compounds
1. write the formula
a) diphosphorus trioxide
b) sulfur hexafluoride
c) dichlorine monoxide
d) iodine gas
2. write the name
a) n₂o₂
b) pcl₃
c) co
d) h₂o
8. show how a compound forms between the following pairs of elements.
a) ca + f
b) li + o

Question

Accepted Answer

# Explanation:
## Step1: Write the formula for ionic compounds
- For beryllium iodide: Beryllium has a charge of $+2$ ($Be^{2+}$) and iodide has a charge of $-1$ ($I^{-}$). Using the criss - cross method, the formula is $BeI_{2}$.
- For aluminum oxide: Aluminum has a charge of $+3$ ($Al^{3+}$) and oxide has a charge of $-2$ ($O^{2 -}$). Using the criss - cross method, the formula is $Al_{2}O_{3}$.
- For barium fluoride: Barium has a charge of $+2$ ($Ba^{2+}$) and fluoride has a charge of $-1$ ($F^{-}$). Using the criss - cross method, the formula is $BaF_{2}$.

## Step2: Name the ionic compounds
- For $K_{2}S$: The cation is potassium ($K^{+}$) and the anion is sulfide ($S^{2 -}$), so the name is potassium sulfide.
- For $NaI$: The cation is sodium ($Na^{+}$) and the anion is iodide ($I^{-}$), so the name is sodium iodide.
- For $Li_{2}O$: The cation is lithium ($Li^{+}$) and the anion is oxide ($O^{2 -}$), so the name is lithium oxide.

## Step3: Write the formula for molecular compounds
- For diphosphorus trioxide: “di -” means 2 for phosphorus and “tri -” means 3 for oxygen, so the formula is $P_{2}O_{3}$.
- For sulfur hexafluoride: “hexa -” means 6 for fluorine, so the formula is $SF_{6}$.
- For dichlorine monoxide: “di -” means 2 for chlorine and “mono -” means 1 for oxygen, so the formula is $Cl_{2}O$.
- For iodine gas: Iodine gas is a diatomic molecule, so the formula is $I_{2}$.

## Step4: Name the molecular compounds
- For $N_{2}O_{2}$: The name is dinitrogen dioxide.
- For $PCl_{3}$: The name is phosphorus trichloride.
- For $CO$: The name is carbon monoxide.
- For $H_{2}O$: The name is dihydrogen monoxide (commonly known as water).

## Step5: Show how compounds form (using electron transfer for ionic compounds)
- For $Ca+F$: Calcium ($Ca$) has 2 valence electrons. It donates 1 electron to each of 2 fluorine ($F$) atoms. Calcium becomes $Ca^{2+}$ and each fluorine becomes $F^{-}$. The compound is $CaF_{2}$.
- For $Li + O$: Lithium ($Li$) has 1 valence electron. Two lithium atoms donate 1 electron each to an oxygen ($O$) atom. Lithium becomes $Li^{+}$ and oxygen becomes $O^{2 -}$. The compound is $Li_{2}O$.

# Answer:
1. a) $BeI_{2}$ b) $Al_{2}O_{3}$ c) $BaF_{2}$
2. a) potassium sulfide b) sodium iodide c) lithium oxide
3. a) $P_{2}O_{3}$ b) $SF_{6}$ c) $Cl_{2}O$ d) $I_{2}$
4. a) dinitrogen dioxide b) phosphorus trichloride c) carbon monoxide d) dihydrogen monoxide (water)
5. a) $Ca + 2F
ightarrow Ca^{2+}+2F^{-}$ (compound $CaF_{2}$) b) $2Li+O
ightarrow 2Li^{+}+O^{2 -}$ (compound $Li_{2}O$)

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QUESTION IMAGE

Question

Explanation:

Step1: Write the formula for ionic compounds

Step2: Name the ionic compounds

Step3: Write the formula for molecular compounds

Step4: Name the molecular compounds

Step5: Show how compounds form (using electron transfer for ionic compounds)

Answer: