Question

r is in the interior of ∠jkm. if m∠jkm = 164° and m∠jkr = 47°, what is the m∠rkm?

Explanation:

Step1: Use angle - addition postulate

If \(R\) is in the interior of \(\angle JKM\), then \(m\angle JKM=m\angle JKR + m\angle RKM\).

Step2: Solve for \(m\angle RKM\)

Rearrange the formula: \(m\angle RKM=m\angle JKM - m\angle JKR\).
Substitute \(m\angle JKM = 164^{\circ}\) and \(m\angle JKR = 47^{\circ}\) into the formula: \(m\angle RKM=164^{\circ}- 47^{\circ}\).
\(m\angle RKM = 117^{\circ}\)

Answer:

\(117^{\circ}\)