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individual practice write the unabbreviated electron configurations of …

Question

individual practice
write the unabbreviated electron configurations of the following elements

  1. neon
  2. oxygen
  3. helium
  4. sodium
  5. lithium
  6. argon
  7. hydrogen

write the abbreviated electron configurations of the following elements

  1. cesium
  2. sulfur
  3. calcium
  4. phosphorus
  5. potassium
  6. strontium
  7. aluminum

the following electron configurations belong to which elements?

  1. 1s² 2s² 2p⁶ 3s¹
  2. 1s² 2s²
  3. kr 5s¹
  4. xe 6s²
  5. xe 6s² 4f¹⁴ 5d¹⁰ 6p²
  6. kr 5s² 4d¹⁰

exit ticket: a friend of yours missed todays lesson and you are helping them catch up.
write below your explanation of how to find an elements electron configuration to them.

Explanation:

1) Neon

Neon has atomic number \(10\).
Electron configuration: \(1s^{2}2s^{2}2p^{6}\)

2) Oxygen

Oxygen has atomic number \(8\).
Electron configuration: \(1s^{2}2s^{2}2p^{4}\)

3) Helium

Helium has atomic number \(2\).
Electron configuration: \(1s^{2}\)

4) Sodium

Sodium has atomic number \(11\).
Electron configuration: \(1s^{2}2s^{2}2p^{6}3s^{1}\)

5) Lithium

Lithium has atomic number \(3\).
Electron configuration: \(1s^{2}2s^{1}\)

6) Argon

Argon has atomic number \(18\).
Electron configuration: \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}\)

7) Hydrogen

Hydrogen has atomic number \(1\).
Electron configuration: \(1s^{1}\)

8) Cesium

Cesium has atomic number \(55\).
Abbreviated electron configuration: \([Xe]6s^{1}\)

9) Sulfur

Sulfur has atomic number \(16\).
Abbreviated electron configuration: \([Ne]3s^{2}3p^{4}\)

10) Calcium

Calcium has atomic number \(20\).
Abbreviated electron configuration: \([Ar]4s^{2}\)

11) Phosphorus

Phosphorus has atomic number \(15\).
Abbreviated electron configuration: \([Ne]3s^{2}3p^{3}\)

12) Potassium

Potassium has atomic number \(19\).
Abbreviated electron configuration: \([Ar]4s^{1}\)

13) Strontium

Strontium has atomic number \(38\).
Abbreviated electron configuration: \([Kr]5s^{2}\)

14) Aluminum

Aluminum has atomic number \(13\).
Abbreviated electron configuration: \([Ne]3s^{2}3p^{1}\)

15) \(1s^{2}2s^{2}2p^{6}3s^{1}\)

Count the electrons (\(2 + 2+6 + 1=11\)).
Element: Sodium

16) \(1s^{2}2s^{2}\)

Count the electrons (\(2+2 = 4\)).
Element: Beryllium

17) \([Kr]5s^{1}\)

Krypton (\(Kr\)) has \(36\) electrons, plus \(1\) more (\(36+1=37\)).
Element: Rubidium

18) \([Xe]6s^{2}\)

Xenon (\(Xe\)) has \(54\) electrons, plus \(2\) more (\(54 + 2=56\)).
Element: Barium

19) \([Xe]6s^{2}4f^{14}5d^{10}6p^{2}\)

Xenon (\(Xe\)) has \(54\) electrons, \(2+14 + 10+2=28\), total \(54+28 = 82\).
Element: Lead

20) \([Kr]5s^{2}4d^{10}\)

Krypton (\(Kr\)) has \(36\) electrons, \(2+10=12\), total \(36+12=48\).
Element: Cadmium

Answer:

  1. \(1s^{2}2s^{2}2p^{6}\)
  2. \(1s^{2}2s^{2}2p^{4}\)
  3. \(1s^{2}\)
  4. \(1s^{2}2s^{2}2p^{6}3s^{1}\)
  5. \(1s^{2}2s^{1}\)
  6. \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}\)
  7. \(1s^{1}\)
  8. \([Xe]6s^{1}\)
  9. \([Ne]3s^{2}3p^{4}\)
  10. \([Ar]4s^{2}\)
  11. \([Ne]3s^{2}3p^{3}\)
  12. \([Ar]4s^{1}\)
  13. \([Kr]5s^{2}\)
  14. \([Ne]3s^{2}3p^{1}\)
  15. Sodium
  16. Beryllium
  17. Rubidium
  18. Barium
  19. Lead
  20. Cadmium