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Question
2.6 (a) independent practice & hw
- the height of a firework at an amusement park celebration can be modeled by a quadratic function. suppose the firework is launched from a platform 2 feet off the ground at a velocity of 96 feet per second.
a. write a function to represent this situation.
b. find and interpret the y-intercept in the context of this situation. c. find and interpret the axis of symmetry in the context of this situation.
d. find and interpret the vertex in the context of this situation. e. find and interpret the x-intercept(s) in the context of this situation.
- malik is participating in a diving championship. for each of his dives, his height above the water can be modeled by a quadratic function. the diving board is 7.5 meters above the water; malik jumps with a velocity of 4.18 meters per second.
a. write a function to represent this situation.
b. find and interpret the y-intercept in the context of this situation. c. find and interpret the axis of symmetry in the context of this situation.
d. find and interpret the vertex in the context of this situation. e. find and interpret the x-intercept(s) in the context of this situation.
Problem 1a: Write the function for the firework's height
Step1: Recall the projectile motion formula
The height \( h(t) \) of an object in projectile motion is given by the quadratic function \( h(t) = -16t^2 + v_0t + h_0 \), where \( v_0 \) is the initial velocity (in feet per second) and \( h_0 \) is the initial height (in feet).
Step2: Identify \( v_0 \) and \( h_0 \)
Here, \( v_0 = 96 \) ft/s (initial velocity) and \( h_0 = 2 \) ft (initial height from the platform).
Step3: Substitute into the formula
Substitute \( v_0 = 96 \) and \( h_0 = 2 \) into \( h(t) = -16t^2 + v_0t + h_0 \). So the function is \( h(t) = -16t^2 + 96t + 2 \).
Step1: Recall the y - intercept definition
The y - intercept of a function \( y = f(t) \) is the value of \( y \) when \( t = 0 \).
Step2: Substitute \( t = 0 \) into the function
For \( h(t)=-16t^2 + 96t + 2 \), when \( t = 0 \), \( h(0)=-16(0)^2+96(0)+2 = 2 \).
Step3: Interpret the y - intercept
In the context of the firework, \( t = 0 \) represents the time when the firework is launched. So the y - intercept \( (0, 2) \) means that at the moment the firework is launched (\( t = 0 \) seconds), its height is 2 feet (which is the height of the platform from which it is launched).
Step1: Recall the formula for the axis of symmetry of a quadratic function
For a quadratic function in the form \( y = ax^2+bx + c \), the axis of symmetry is given by \( t=-\frac{b}{2a} \).
Step2: Identify \( a \) and \( b \) from \( h(t)=-16t^2 + 96t + 2 \)
Here, \( a=-16 \) and \( b = 96 \).
Step3: Calculate the axis of symmetry
Substitute \( a=-16 \) and \( b = 96 \) into \( t =-\frac{b}{2a} \). So \( t=-\frac{96}{2\times(-16)}=-\frac{96}{-32}=3 \).
Step4: Interpret the axis of symmetry
The axis of symmetry \( t = 3 \) means that the firework reaches its maximum height at \( t = 3 \) seconds. The parabola (graph of the height function) is symmetric about the line \( t = 3 \). So the time before \( t = 3 \) seconds and the time after \( t = 3 \) seconds (at equal distances from \( t = 3 \)) will have the same height.
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\( h(t) = -16t^2 + 96t + 2 \)