Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

independent practice -- 8 problems (spa coefficients) 1. h₂ + cl₂ → __ …

Question

independent practice -- 8 problems (spa coefficients)

  1. h₂ + cl₂ → __ hcl
  2. c + o₂ → co₂
  3. al + o₂ → __ al₂o₃
  4. kclo₃ → kcl + __ o₂
  5. ca(oh)₂ + hcl → cacl₂ + h₂o
  6. fe + __ hcl → fecl₂ + h₂
  7. c₃h₆ + o₂ → co₂ + h₂o
  8. p₄ + o₂ → p₂o₅

Explanation:

Step1: Balance the first equation

For \(H_2 + Cl_2 \to HCl\), count the number of \(H\) and \(Cl\) atoms. There are 2 \(H\) and 2 \(Cl\) on the left. So, we need 2 \(HCl\) on the right.
\(H_2+Cl_2 = 2HCl\)

Step2: Check the second equation

For \(C + O_2\to CO_2\), there is 1 \(C\) and 2 \(O\) on the left, and 1 \(C\) and 2 \(O\) on the right. It is already balanced.
\(C + O_2=CO_2\)

Step3: Balance the third equation

For \(Al+O_2\to Al_2O_3\), use the least - common multiple method. The LCM of 2 (from \(O_2\)) and 3 (from \(Al_2O_3\)) for \(O\) atoms is 6. So, we need \(3O_2\) and \(2Al_2O_3\). Then balance \(Al\) atoms: \(4Al + 3O_2=2Al_2O_3\)

Step4: Balance the fourth equation

For \(KClO_3\to KCl + O_2\), the LCM of 2 (from \(O_2\)) and 3 (from \(KClO_3\)) for \(O\) atoms is 6. So, we need \(2KClO_3\) and \(3O_2\). Then balance \(K\) and \(Cl\) atoms: \(2KClO_3 = 2KCl+3O_2\)

Step5: Balance the fifth equation

For \(Ca(OH)_2+HCl\to CaCl_2 + H_2O\), balance \(Cl\) atoms first. We need \(2HCl\). Then balance \(H\) and \(O\) atoms: \(Ca(OH)_2 + 2HCl=CaCl_2+2H_2O\)

Step6: Balance the sixth equation

For \(Fe + HCl\to FeCl_2+H_2\), balance \(Cl\) atoms. We need \(2HCl\). Then balance \(H\) atoms: \(Fe + 2HCl=FeCl_2+H_2\)

Step7: Balance the seventh equation

For \(C_3H_6+O_2\to CO_2 + H_2O\), balance \(C\) atoms first: \(C_3H_6+O_2\to 3CO_2+H_2O\). Then balance \(H\) atoms: \(C_3H_6+O_2\to 3CO_2 + 3H_2O\). Now balance \(O\) atoms: \(2C_3H_6+9O_2 = 6CO_2+6H_2O\)

Step8: Balance the eighth equation

For \(P_4+O_2\to P_2O_5\), balance \(P\) atoms first: \(P_4+O_2\to 2P_2O_5\). Then balance \(O\) atoms: \(P_4 + 5O_2=2P_2O_5\)

Answer:

  1. \(2\)
  2. \(1\) (already balanced)
  3. \(4\), \(3\), \(2\)
  4. \(2\), \(2\), \(3\)
  5. \(2\), \(2\)
  6. \(2\)
  7. \(2\), \(9\), \(6\), \(6\)
  8. \(5\), \(2\)