Question

1. identify the reaction type, the reactants, and the products.

reaction
aqueous solutions of potassium hydroxide and cobalt(iii) nitrate are mixed.
reaction type
reactant(s)
product(s)
choices:
cono₃
co(no₃)₃
co₃n
co₃no
koh
con
co₃oh
co(oh)₃
kno₃
cooh
k(no₃)₃
co₃k
oh(no₃)₃

Explanation:

Step1: Identify Reaction Type

This is a double - displacement (precipitation) reaction. In double - displacement reactions, the cations and anions of two ionic compounds exchange places. The general form is \(AB + CD
ightarrow AD+CB\). For the reaction between potassium hydroxide (\(KOH\)) and cobalt(III) nitrate (\(Co(NO_3)_3\)), the ions will exchange.

Step2: Identify Reactants

The reactants are potassium hydroxide (\(KOH\)) and cobalt(III) nitrate (\(Co(NO_3)_3\)). So the reactants are \(KOH\) and \(Co(NO_3)_3\).

Step3: Determine Products

When \(KOH\) (ions \(K^+\) and \(OH^-\)) and \(Co(NO_3)_3\) (ions \(Co^{3 + }\) and \(NO_3^-\)) react, the \(K^+\) will combine with \(NO_3^-\) to form \(KNO_3\) and \(Co^{3+}\) will combine with \(OH^-\) to form \(Co(OH)_3\) (since cobalt has a + 3 charge and hydroxide has a - 1 charge, the formula is \(Co(OH)_3\) to balance the charges: \(3\times(- 1)+( + 3)=0\)).

Answer:

• Reaction Type: Double - Displacement (Precipitation)
• Reactant(s): \(KOH\) + \(Co(NO_3)_3\)
• Product(s): \(KNO_3\) + \(Co(OH)_3\)