Question

identify the acid-base reaction.
\\(\ce{h2 (g) + cuo (s) -> cu (s) + h2o (l)}\\)
\\(\ce{agno3 (aq) + nacl (aq) -> agcl (s) + nano3 (aq)}\\)
there is no acid-base reaction.
\\(\ce{2 hclo4 (aq) + sr(oh)2 (aq) -> sr(clo4)2 (aq) + 2 h2o (l)}\\)

Explanation:

Step1: Recall acid-base reaction definition

Acid-base reactions (neutralization) involve an acid (donates \(H^+\)) and a base (donates \(OH^-\) or accepts \(H^+\)) forming a salt and water.

Step2: Analyze each option

• Option 1: \(H_2(g) + CuO(s)

ightarrow Cu(s) + H_2O(l)\)
This is a redox reaction (oxidation of \(H_2\), reduction of \(CuO\)), not acid-base.

• Option 2: \(AgNO_3(aq) + NaCl(aq)

ightarrow AgCl(s) + NaNO_3(aq)\)
This is a precipitation reaction (double displacement, forms \(AgCl\) precipitate), not acid-base.

• Option 3: "No acid-base reaction" is incorrect (see next).
• Option 4: \(2HClO_4(aq) + Sr(OH)_2(aq)

ightarrow Sr(ClO_4)_2(aq) + 2H_2O(l)\)
\(HClO_4\) (acid, donates \(H^+\)) reacts with \(Sr(OH)_2\) (base, donates \(OH^-\)) to form salt (\(Sr(ClO_4)_2\)) and water. This fits neutralization (acid-base) reaction.

Answer:

\(2\ \text{HClO}_4\ (aq) + \text{Sr(OH)}_2\ (aq) \longrightarrow \text{Sr(ClO}_4\text{)}_2\ (aq) + 2\ \text{H}_2\text{O}\ (l)\) (the fourth option)