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4 hw #2 savvas lesson 2-6 question 4, 2.5.ps-13 find the distance betwe…

Question

4 hw #2 savvas lesson 2-6 question 4, 2.5.ps-13 find the distance between the pair of points. (-5, -1) and (-5, -8) unit(s)

Explanation:

Step1: Identify the formula

The distance formula between two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\). Here \(x_1=-5,y_1=-1,x_2=-5,y_2 = - 8\).

Step2: Substitute the values

Substitute into the formula: \(d=\sqrt{(-5-(-5))^2+(-8 - (-1))^2}\).
Simplify the expressions inside the square - root:
\(x\) - difference: \(-5-(-5)=-5 + 5=0\)
\(y\) - difference: \(-8-(-1)=-8 + 1=-7\)
So \(d=\sqrt{0^2+(-7)^2}\)

Step3: Calculate the distance

\(d=\sqrt{0 + 49}=\sqrt{49}\)
Since \(\sqrt{49}=7\)

Answer:

\(7\)