Question

a humpback whale was 6,600 meters north of billet bay, swimming south at a constant velocity. if it swam one - third of the distance to the bay in 10 minutes, what was the whales velocity? write your answer as a whole number.
□ meters per minute to the south
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Explanation:

Step1: Find the distance swam

The total distance to the bay is 6600 meters. The whale swam one - third of this distance. So the distance \(d\) swam is \(\frac{1}{3}\times6600\) meters.
\(\frac{1}{3}\times6600 = 2200\) meters.

Step2: Calculate velocity

Velocity \(v\) is given by the formula \(v=\frac{d}{t}\), where \(d\) is the distance and \(t\) is the time. Here, \(d = 2200\) meters and \(t=10\) minutes.
So \(v=\frac{2200}{10}=220\) meters per minute.

Answer:

220