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Explanation:

Identify given values and geometric relationships

The problem asks for the measure of arc \(\widehat{GH}\).
From the diagram, we have a circle centered at \(D\).
The line segment \(CG\) is a diameter passing through the center \(D\).
We are given:

  • The measure of arc \(\widehat{CE} = 57^\circ\).
  • The measure of arc \(\widehat{FG} = 57^\circ\).
  • The angles \(\angle CDE \cong \angle GDH\).

Relate central angles to arc measures

Since the measure of an arc is equal to the measure of its corresponding central angle:

  • \(m\angle CDE = m\widehat{CE} = 57^\circ\).
  • Since \(\angle CDE \cong \angle GDH\), we have \(m\angle GDH = m\angle CDE = 57^\circ\).

Calculate the measure of arc GH

The central angle corresponding to arc \(\widehat{GH}\) is \(\angle GDH\).
Therefore:

$$ m\widehat{GH} = m\angle GDH = 57^\circ $$

However, looking at the options: \(114^\circ\), \(123^\circ\), \(228^\circ\), \(246^\circ\).
Let's re-examine the diagram and the given statement: "In circle D, \(\angle EDF \cong \angle GDH\)".
Let's recalculate with this relation:

  • Since \(CG\) is a straight line (diameter), the sum of angles on a straight line is \(180^\circ\):
$$ m\angle CDE + m\angle EDF + m\angle FDG = 180^\circ $$
  • We know \(m\angle CDE = m\widehat{CE} = 57^\circ\) and \(m\angle FDG = m\widehat{FG} = 57^\circ\) (since \(F\) is on the diameter line or adjacent, the arc \(\widehat{FG} = 57^\circ\)).
  • Thus:
$$ 57^\circ + m\angle EDF + 57^\circ = 180^\circ \implies m\angle EDF = 180^\circ - 114^\circ = 66^\circ $$
  • Since \(\angle EDF \cong \angle GDH\):
$$ m\angle GDH = m\angle EDF = 66^\circ \implies m\widehat{GH} = 66^\circ $$

This does not match the options. Let's re-read the statement: "In circle D, \(\angle CDE \cong \angle GDH\)"? No, the text at the top left says: "In circle D, \(\angle EDF \cong \angle GDH\)".
Wait, let's look at the arc values: the top arc is \(57^\circ\), the bottom arc is \(57^\circ\).
If the total angle of the semi-circle \(CEFG\) is \(180^\circ\):
The arcs are \(\widehat{CE} = 57^\circ\), \(\widehat{EF} = x\), \(\widehat{FG} = 57^\circ\).
Since \(CG\) is a diameter, \(m\widehat{CE} + m\widehat{EF} + m\widehat{FG} = 180^\circ \implies 57^\circ + m\widehat{EF} + 57^\circ = 180^\circ \implies m\widehat{EF} = 66^\circ\).
The central angle \(m\angle EDF = m\widehat{EF} = 66^\circ\).
If \(\angle EDF \cong \angle GDH\), then \(m\angle GDH = 66^\circ\), so \(m\widehat{GH} = 66^\circ\).
Wait, is the question asking for the major arc \(\widehat{EGH}\)?
Let's calculate \(m\widehat{EGH}\):

$$ m\widehat{EGH} = 360^\circ - m\widehat{CE} - m\widehat{FG} - m\widehat{EF} \text{ (excluding some parts)} $$

Or:

$$ m\widehat{EGH} = m\widehat{EF} + m\widehat{FG} + m\widehat{GH} = 66^\circ + 57^\circ + 66^\circ = 189^\circ $$

What about the major arc \(\widehat{EH}\)?

$$ m\widehat{EH} = m\widehat{EF} + m\widehat{FG} + m\widehat{GH} = 66^\circ + 57^\circ + 66^\circ = 189^\circ $$

What about the arc \(\widehat{EGH}\) if it goes the long way?
Let's check the options:

  • If \(m\widehat{GH} = 114^\circ\): this is \(57^\circ \times 2\).
  • If the given statement is \(\angle CDE \cong \angle GDH\), then \(m\angle GDH = 57^…

Answer:

  • (A) \(114^\circ\)
  • (B) \(123^\circ\)
  • (C) \(228^\circ\)
  • (D) \(246^\circ\) (Correct answer)