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Identify the given values and geometric components
The figure consists of two curved sectors sharing a boundary.
- The curved parts of the figure are circular arcs centered at points \(A\) and \(C\).
- For the arc \(DE\) centered at \(C\):
- The radius \(CD = 5\).
- The central angle \(\angle DCE = 30^\circ\).
- For the arc \(BE\) centered at \(A\):
- The radius \(AB = 5\).
- The central angle \(\angle BAE = 120^\circ\).
- We need to find the approximate perimeter of the shaded region.
- The boundary of the shaded region consists of:
- Straight segment \(AB\) of length \(5\).
- Circular arc \(BE\) centered at \(A\) with radius \(5\) and central angle \(120^\circ\).
- Straight segment \(CD\) of length \(5\).
- Circular arc \(DE\) centered at \(C\) with radius \(5\) and central angle \(30^\circ\).
- Use \(\pi \approx 3.14\) and round the final answer to one decimal place.
Calculate the length of arc BE
The formula for the arc length of a sector is:
$$
L = \frac{\theta}{360^\circ} \times 2\pi r
$$
For arc \(BE\):
- Radius \(r_1 = 5\)
- Angle \(\theta_1 = 120^\circ\)
$$
L_{BE} = \frac{120}{360} \times 2 \times 3.14 \times 5 = \frac{1}{3} \times 31.4 \approx 10.47
$$
Calculate the length of arc DE
For arc \(DE\):
- Radius \(r_2 = 5\)
- Angle \(\theta_2 = 30^\circ\)
$$
L_{DE} = \frac{30}{360} \times 2 \times 3.14 \times 5 = \frac{1}{12} \times 31.4 \approx 2.62
$$
Sum the boundary lengths to find the perimeter
The total perimeter \(P\) is the sum of the two straight segments and the two arcs:
$$
P = AB + L_{BE} + CD + L_{DE}
$$
Substitute the values:
$$
P = 5 + 10.47 + 5 + 2.62 = 23.09
$$
Rounding to one decimal place gives \(23.1\).
Match with the multiple-choice options
Let's look at the visible options in the image:
- Option 1: \(17.3\)
- Option 2: \(23.0\)
- Option 3: \(23.1\)
- Option 4: \(28.1\)
Our calculated value of \(23.1\) matches the third option.
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- (A) 17.3
- (B) 23.0
- (C) 23.1 (Correct answer)
- (D) 28.1