Question

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Explanation:

Step1: Identify standard quadratic form

A quadratic equation is $ax^2+bx+c=0$. For $-2x^2+98=0$, we rewrite it as $-2x^2+0x+98=0$.

Step2: Assign a, b, c values

$a=-2$, $b=0$, $c=98$

Step3: Substitute into quadratic formula

The quadratic formula is $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$. Substitute the values:
$x=\frac{-(0)\pm\sqrt{(0)^2-4(-2)(98)}}{2(-2)}$

Step4: Simplify to find x values

First calculate discriminant: $\sqrt{0 + 784}=\sqrt{784}=28$
Then $x=\frac{0\pm28}{-4}$, so $x=\frac{28}{-4}=-7$ or $x=\frac{-28}{-4}=7$

Answer:

$a=-2$, $b=0$, $c=98$
$x = \frac{-(0)\pm\sqrt{(0)^2-4(-2)(98)}}{2(-2)}$
Solutions: $x=7$ and $x=-7$