Question

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Explanation:

Step1: Recall linear function form

A linear function is of the form \( y = mx + b \), where \( m \) (slope) and \( b \) (y - intercept) are constants, and the exponent of \( x \) is 1.

Step2: Analyze \( y=\sqrt{3x} \)

The equation \( y = \sqrt{3x}=(3x)^{\frac{1}{2}} = 3^{\frac{1}{2}}x^{\frac{1}{2}}\). The exponent of \( x \) here is \( \frac{1}{2} \), not 1. So it cannot be written in the form \( y=mx + b \).

Step3: Determine function type

Since it cannot be written in the linear function form \( y = mx + b \), it is a nonlinear function.

Answer:

Blank 1: cannot; Blank 2: nonlinear