Question

how can we protect pups paws?
the dog in the gif above is wearing boots! while this may look silly and cute, boots like
this can protect dogs feet from cuts and burns.

1. a student performs an investigation by placing the silicone

rubber boot on a brick. the student finds that the temperature
of the boot changed from 20°c to 22°c over the course of the
investigation. the student then calculated the change in
thermal energy of the boot. drag and drop the values into the
correct locations in the formula to find the thermal energy
q = mcδt
q = (g)(j/g°c)(°c)
this result will provide the thermal energy that was lost by the
and gained by the
drag the answers below into the grey placeholders above
1.2 dog boot 22 2 50 element surface 1,000
1.8 20

Explanation:

Step1: Identify variables in the formula

In the formula \(Q = mc\Delta T\), \(m\) is mass, \(c\) is specific - heat capacity, \(\Delta T\) is temperature change.
Assume the mass \(m = 50\space g\) (a reasonable value from the given options for the mass of a small boot - like object), the specific - heat capacity \(c = 1.2\space J/g^{\circ}C\) (a common value for some rubber - like materials), and \(\Delta T=T_{final}-T_{initial}=22 - 20=2^{\circ}C\)

Step2: Fill in the formula

Substitute the values into the formula \(Q=(50\space g)(1.2\space J/g^{\circ}C)(2^{\circ}C)\)

Step3: Analyze heat transfer

According to the law of conservation of energy, the thermal energy lost by the element surface (which was at a higher temperature initially, transferring heat to the boot) is gained by the dog boot.

Answer:

\(Q=(50\space g)(1.2\space J/g^{\circ}C)(2^{\circ}C)\); lost by the element surface and gained by the dog boot.