Question

how much voltage is required to run 0.64 a of current through a 240 ω resistor? use \\( \delta v = ir \\).

a. \\( 1.5 \times 10^{2} v \\)
b. \\( 6.5 \times 10^{-3} v \\)
c. \\( 2.7 \times 10^{-3} v \\)
d. \\( 3.8 \times 10^{2} v \\)

Explanation:

Step1: Substitute values into formula

Given \(I = 0.64\space A\) and \(R=240\space\Omega\), substitute into \(\Delta V = IR\). So \(\Delta V=0.64\times240\).

Step2: Calculate the product

\(0.64\times240=(0.6 + 0.04)\times240=0.6\times240+0.04\times240 = 144+9.6=153.6\). In scientific notation, \(153.6 = 1.536\times10^{2}\approx1.5\times 10^{2}\).

Answer:

A. \(1.5\times 10^{2}V\)