Question

1. how much heat must be added to a 36.2 g sample of iron to increase its temperature by 250.0°c?

Explanation:

Step1: Identify the formula

The formula for heat transfer is \(Q = mc\Delta T\), where \(Q\) is the heat added, \(m\) is the mass, \(c\) is the specific - heat capacity, and \(\Delta T\) is the change in temperature.

Step2: Substitute the values

From the table, the specific - heat capacity of iron \(c=0.449\space J/(g\cdot^{\circ}C)\), the mass \(m = 36.2\space g\), and the change in temperature \(\Delta T=250.0^{\circ}C\).
Substitute these values into the formula: \(Q=(36.2\space g)\times(0.449\space J/(g\cdot^{\circ}C))\times(250.0^{\circ}C)\)

Step3: Calculate the value

First, calculate \(36.2\times0.449 = 16.2538\). Then, \(16.2538\times250.0=4063.45\space J\)

Answer:

\(4063.45\space J\)