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how many valence electrons must be accounted for in the lewis structure…

Question

how many valence electrons must be accounted for in the lewis structure of chloroethane (
c₂h₅cl)?
18
24
13
20

Explanation:

Step1: Determine valence electrons of each atom

Carbon (\(C\)) has \(4\) valence electrons. There are \(2\) carbon atoms, so \(2\times4 = 8\) valence electrons from \(C\).
Hydrogen (\(H\)) has \(1\) valence electron. There are \(5\) hydrogen atoms, so \(5\times1=5\) valence electrons from \(H\).
Chlorine (\(Cl\)) has \(7\) valence electrons. There is \(1\) chlorine atom, so \(7\times1 = 7\) valence electrons from \(Cl\).

Step2: Sum up the valence electrons

$$8 + 5+7=20$$

Answer:

\(20\)