Question

how many total atoms in the following compound. (1.4 points)
extra content
4k₂co₃
a. 4
b. 12
c. 18
d. 24
question 17 of 29
how many total atoms are present in the following compound? c₆h₁₂o₆ (6.8 points)
a. 6
b. 12
c. 18
d. 24
question 18 of 29
how many total atoms? (1.4 points)
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5ga₂(cr₂o₇)₃
a. 10
b. 30
c. 55
d. 145
question 19 of 29
how many total atoms of carbon are present in the products? (6.8 points)
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6co₂ + 6h₂o → c₆h₁₂o₆ + 6o₂
a. 6
b. 12
c. 18
d. 24

Explanation:

Step1: Analyze \(4K_2CO_3\)

In \(K_2CO_3\), there are \(2\) K atoms, \(1\) C atom and \(3\) O atoms. So in one \(K_2CO_3\) unit, there are \(2 + 1+3=6\) atoms. For \(4K_2CO_3\), the total number of atoms is \(4\times6 = 24\).

Step2: Analyze \(C_6H_{12}O_6\)

In \(C_6H_{12}O_6\), there are \(6\) C atoms, \(12\) H atoms and \(6\) O atoms. The total number of atoms is \(6 + 12+6=24\).

Step3: Analyze \(5Ga_2(Cr_2O_7)_3\)

In \(Ga_2(Cr_2O_7)_3\), there are \(2\) Ga atoms, \(2\times3 = 6\) Cr atoms and \(7\times3=21\) O atoms. So in one \(Ga_2(Cr_2O_7)_3\) unit, there are \(2+6 + 21=29\) atoms. For \(5Ga_2(Cr_2O_7)_3\), the total number of atoms is \(5\times29=145\).

Step4: Analyze carbon atoms in \(6CO_2+6H_2O

ightarrow C_6H_{12}O_6 + 6O_2\)
In the products, \(C_6H_{12}O_6\) has \(6\) C atoms and \(6O_2\) has \(0\) C atoms. So the total number of carbon atoms in the products is \(6\).

Answer:

For \(4K_2CO_3\): D. 24
For \(C_6H_{12}O_6\): D. 24
For \(5Ga_2(Cr_2O_7)_3\): D. 145
For carbon atoms in \(6CO_2+6H_2O
ightarrow C_6H_{12}O_6 + 6O_2\): A. 6