Question

how many nitrogen atoms are present in one mole of dinitrogen pentoxide? n₂o₅ 6.02 x 10²³ atoms 3.01 x 10²⁴ atoms 4.21 x 10²⁴ atoms 1.20 x 10²⁴ atoms

Explanation:

Step1: Recall Avogadro's number and formula

Avogadro's number is \( 6.02\times10^{23} \) particles per mole. The formula for dinitrogen pentoxide is \( N_2O_5 \), which means there are 2 nitrogen atoms per molecule of \( N_2O_5 \).

Step2: Calculate moles of nitrogen atoms

1 mole of \( N_2O_5 \) contains 2 moles of N atoms (from the subscript 2 in \( N_2O_5 \)).

Step3: Calculate number of nitrogen atoms

Using Avogadro's number, the number of N atoms is moles of N × Avogadro's number. Moles of N = 2 (from 1 mole of \( N_2O_5 \)), so number of N atoms = \( 2\times6.02\times10^{23} = 1.204\times10^{24} \approx 1.20\times10^{24} \) atoms.

Answer:

1.20 x 10²⁴ atoms