Question

how many moles of nitrogen are contained in 18.7 l at stp? ? mol

Explanation:

Step1: Recall STP molar volume

At STP (Standard Temperature and Pressure, 0°C and 1 atm), 1 mole of any ideal gas occupies 22.4 L. So the molar volume \( V_m = 22.4 \, \text{L/mol} \).

Step2: Use the formula \( n=\frac{V}{V_m} \)

We have the volume \( V = 18.7 \, \text{L} \) and \( V_m = 22.4 \, \text{L/mol} \). Substitute into the formula: \( n=\frac{18.7}{22.4} \).

Step3: Calculate the value

\( n=\frac{18.7}{22.4}\approx0.835 \, \text{mol} \) (rounded to three decimal places).

Answer:

\( \approx0.835 \)