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how many moles of nitrogen are contained in 18.7 l at stp?

Question

how many moles of nitrogen are contained in 18.7 l at stp?

Explanation:

Step1: Recall STP molar volume

At STP, 1 mole of gas = 22.4 L

Step2: Calculate moles of nitrogen

Moles = Volume / Molar volume = $\frac{18.7}{22.4}$

Step3: Compute the result

$\frac{18.7}{22.4} \approx 0.835$

Answer:

0.835