Question

how many moles of nacl are in 2.35 liters of a 3.27e+0 m solution?

Explanation:

Step1: Recall the formula for molarity

Molarity ($M$) is defined as $M=\frac{n}{V}$, where $n$ is the number of moles and $V$ is the volume in liters. We can rearrange this formula to solve for $n$: $n = M\times V$.

Step2: Substitute the given values

Given $M = 3.27$ (since $3.27e + 0=3.27$) and $V=2.35$ L.

$$ n=(3.27\space M)\times(2.35\space L) $$

$$ n = 3.27\times2.35 $$

$$ n=7.6845 $$

Answer:

$7.68$ moles (rounded to three significant figures)