Question

how many moles of argon occupy a volume of 18.6 l at stp?
0.830 moles
8.30 moles
32.0 moles
1.57 moles
4.67 moles

Explanation:

Step1: Recall the molar volume at STP

At standard temperature and pressure (STP), the molar volume of any ideal gas is \(V_m = 22.4\space L/mol\). The formula to find the number of moles \(n\) is \(n=\frac{V}{V_m}\), where \(V\) is the volume of the gas.

Step2: Substitute the given values

We are given \(V = 18.6\space L\) and \(V_m=22.4\space L/mol\). Substituting these values into the formula \(n=\frac{V}{V_m}\), we get \(n=\frac{18.6}{22.4}\).

Step3: Calculate the number of moles

\(n=\frac{18.6}{22.4}\approx0.830\space mol\)

Answer:

0.830 moles