Question

5
how many moles of air are there in a 3 l container at 1 atm pressure and 293 k? use ( pv = nrt ).
a. 0.125 moles
b. 8.02 moles
c. 0.042 moles
d. 36.54 moles

Explanation:

Step1: Rearrange the ideal gas law formula

The ideal gas law is \(PV = nRT\). We want to solve for \(n\) (moles), so we rearrange the formula to \(n=\frac{PV}{RT}\).

Step2: Identify the values of \(P\), \(V\), \(R\), and \(T\)

• \(P = 1\space atm\)
• \(V=3\space L\)
• \(R = 0.0821\space L\cdot atm/(mol\cdot K)\) (gas constant)
• \(T = 293\space K\)

Step3: Substitute the values into the formula

$$
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$$

Answer:

A. 0.125 moles