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1. how many molecules of sulfur tetrafluoride are present in 2.73 moles…

Question

  1. how many molecules of sulfur tetrafluoride are present in 2.73 moles of this compound? 2. how many moles of sulfur tetrafluoride are present in 4.47×10^22 molecules of this compound? use the references to access important values if needed for this question. 9 more group attempts remaining

Explanation:

Step1: Recall Avogadro's number

Avogadro's number ($N_A$) is $6.022\times 10^{23}$ molecules/mol.

Step2: Calculate number of molecules for question 1

We know the number of moles $n = 2.73$ mol. Using the formula $N=n\times N_A$, we have $N = 2.73\times6.022\times 10^{23}$ molecules.
$N=2.73\times6.022\times 10^{23}=1.644006\times 10^{24}$ molecules.

Step3: Calculate number of moles for question 2

We know the number of molecules $N = 4.47\times 10^{22}$ molecules. Using the formula $n=\frac{N}{N_A}$, we substitute $N_A = 6.022\times 10^{23}$ molecules/mol.
$n=\frac{4.47\times 10^{22}}{6.022\times 10^{23}}=\frac{4.47}{60.22}\approx0.0742$ moles.

Answer:

  1. $1.64\times 10^{24}$ molecules
  2. $0.0742$ moles