Question

1. how many ml of a 6.00 ppm solution are needed to make 4.00 l of a 0.100 ppm solution?

first, we have to identify the variables
$c_c = 1$ ppm $c_d = 2$ ppm
$v_c =?$ $v_d = 4.00 l$
arrange the equation to solve for $v_c$ then put numbers,
$v_c = \frac{(3 ppm)(4 l)}{6 ppm} = 5 l$
$7 ml$
$(8 l)(\frac{}{1 l}) = 66.7 ml$

1. what is the dilution factor?

$dilution = \frac{9 m}{10 m} = \frac{1}{60}$
a. 36.00 b. 5.00 c. 31.00 d. 150.0 e. 12 f. 350.00
g. 100.0 h. $2.4×10^{-2}$ i. $1.2×10^{-3}$ j. 1.786 k. 7.143 l. 25.00
m. 7.500 n. 125.0 o. 500.0 p. 15.00 q. 185.00 r. 444.44
s. $2.00×10^{3}$ t. 20.67 u. 0.500 v. 499.5 w. 15 x. 33.33

Explanation:

Step1: Identify the formula for dilution

The formula for dilution is \(C_{C}V_{C}=C_{D}V_{D}\), where \(C_{C}\) is the concentration of the concentrated solution, \(V_{C}\) is the volume of the concentrated solution, \(C_{D}\) is the concentration of the diluted solution, and \(V_{D}\) is the volume of the diluted solution.

Step2: Substitute the given values into the formula

We are given \(C_{C} = 6.00\) ppm, \(C_{D}=0.100\) ppm, and \(V_{D} = 4.00\) L. Substituting these values into the formula \(V_{C}=\frac{C_{D}V_{D}}{C_{C}}\), we get \(V_{C}=\frac{0.100\space ppm\times4.00\space L}{6.00\space ppm}\).

Step3: Calculate the volume \(V_{C}\)

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Step4: Convert liters to milliliters

Since \(1\space L = 1000\space mL\), we convert \(V_{C}\) to milliliters: \(V_{C}=0.0667\space L\times1000\space mL/L = 66.7\space mL\)

Answer:

\(V_{C} = 66.7\space mL\)