Question

homework: module a part 1 review
score: 22/30 answered: 24/30
question 25
subtract: 13\frac{4}{15}-5\frac{3}{5}
question help: post to forum

Explanation:

Step1: Convert mixed - numbers to improper fractions

$13\frac{4}{15}=\frac{13\times15 + 4}{15}=\frac{195+4}{15}=\frac{199}{15}$ and $5\frac{3}{5}=\frac{5\times5 + 3}{5}=\frac{25 + 3}{5}=\frac{28}{5}$.

Step2: Find a common denominator

The common denominator of 15 and 5 is 15. Rewrite $\frac{28}{5}$ with a denominator of 15: $\frac{28}{5}=\frac{28\times3}{5\times3}=\frac{84}{15}$.

Step3: Subtract the fractions

$\frac{199}{15}-\frac{84}{15}=\frac{199 - 84}{15}=\frac{115}{15}$.

Step4: Simplify the fraction

$\frac{115}{15}=\frac{23}{3}=7\frac{2}{3}$.

Answer:

$7\frac{2}{3}$