Question

home > math& 141 (precalculus i) fall 2025 ls online > assessment intermediate algebra diagnostic score: 4/20 answered: 4/20 question 5 solve this system of equations {2x - 3y = -7 {4x + y = -7 x = y = enter an integer or decimal number more...

Explanation:

Step1: Multiply the second - equation by 3

Multiply $4x + y=-7$ by 3 to get $12x + 3y=-21$.

Step2: Add the new - equation to the first equation

$(2x-3y)+(12x + 3y)=-7+( - 21)$.
$2x-3y+12x + 3y=-7 - 21$.
$14x=-28$.
$x = - 2$.

Step3: Substitute $x=-2$ into the second equation

Substitute $x = - 2$ into $4x + y=-7$.
$4\times(-2)+y=-7$.
$-8 + y=-7$.
$y=-7 + 8=1$.

Answer:

$x=-2$
$y = 1$