Question

home > fall 2025 math195 tuesday/thursday > asse
assignment 7.1: angles
score: 12/27 answered: 7/13
question 8
find an angle between 0° and 360° that is coter
631° is coterminal to
-204° is coterminal to
-1242° is coterminal to
4412° is coterminal to
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Explanation:

Step1: Find coterminal angle for \(631^{\circ}\)

Subtract \(360^{\circ}\) from \(631^{\circ}\): \(631 - 360=271^{\circ}\)

Step2: Find coterminal angle for \(- 204^{\circ}\)

Add \(360^{\circ}\) to \(-204^{\circ}\): \(-204 + 360 = 156^{\circ}\)

Step3: Find coterminal angle for \(-1242^{\circ}\)

First, divide \(-1242\) by \(360\): \(-1242\div360=-3.45\). Take the integer part \(- 3\). Then add \(360\times4\) (because we want a positive angle) to \(-1242^{\circ}\). \(-1242+360\times4=-1242 + 1440=198^{\circ}\)

Step4: Find coterminal angle for \(4412^{\circ}\)

Divide \(4412\) by \(360\): \(4412\div360 = 12.255\cdots\). Take the integer part \(12\). Subtract \(360\times12\) from \(4412^{\circ}\). \(4412-360\times12=4412 - 4320=92^{\circ}\)

Answer:

\(271\), \(156\), \(198\), \(92\)