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Question
- henry throws a 650 - gram stone off of a cliff. what is the apparent weight of the stone while it is in free fall? - 6.4n 0n 12.8n 6.4n
Step1: Recall the concept of apparent weight in free - fall
Apparent weight \(W_{app}\) is given by the formula \(W_{app}=m(g - a)\), where \(m\) is the mass of the object, \(g\) is the acceleration due to gravity (\(g = 9.8\ m/s^{2}\)), and \(a\) is the acceleration of the object.
Step2: Determine the acceleration of the stone in free - fall
When an object is in free - fall, its acceleration \(a = g\).
Step3: Calculate the apparent weight
Substitute \(a = g\) into the formula \(W_{app}=m(g - a)\). Then \(W_{app}=m(g - g)=m\times0 = 0\)
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B. \(0N\)