Question

1. a helicopter travelling at a velocity of 15 m/s w accelerates uniformly at a rate of 7.0 m/s2 e for 4.0 s. what is the helicopters final velocity?

Explanation:

Step1: Define the variables

Let the initial velocity \(v_{0}=- 15\ m/s\) (taking west as negative and east as positive), acceleration \(a = 7.0\ m/s^{2}\), time \(t = 4.0\ s\).

Step2: Use the kinematic equation \(v=v_{0}+at\)

Substitute the values into the equation: \(v=-15+7.0\times4.0\).
First, calculate \(7.0\times4.0 = 28\). Then \(v=-15 + 28\).

Step3: Calculate the final velocity

\(v=13\ m/s\) (the positive sign indicates the direction is east).

Answer:

The helicopter's final velocity is \(13\ m/s\) [E].