he law of sines to solve for x. r

Question

Accepted Answer

# Explanation:
## Step1: Recall the Law of Sines formula
The Law of Sines states that $\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}$. In this triangle, if we let the side opposite the $34^{\circ}$ angle be $5$, the side opposite the $27^{\circ}$ angle be $x$. So, $\frac{x}{\sin27^{\circ}}=\frac{5}{\sin34^{\circ}}$.
## Step2: Solve for $x$
$$
\begin{align*}
x&=\frac{5\times\sin27^{\circ}}{\sin34^{\circ}}\
\sin27^{\circ}&\approx0.454, \sin34^{\circ}\approx0.559\
x&=\frac{5\times0.454}{0.559}\
x&=\frac{2.27}{0.559}\
x&\approx4.06
\end{align*}
$$

# Answer:
$x\approx4.06$

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Question

Explanation:

Step1: Recall the Law of Sines formula

Step2: Solve for \(x\)

Answer: