Question

hcl(aq) + ba(oh)₂(aq) →
express your answer as a chemical equation including phases.
a chemical reaction does not occur for this question
submit request answer
part b
h₂so₄(aq) + koh(aq) →
express your answer as a chemical equation including phases.
a chemical reaction does not occur for this question
submit request answer

Explanation:

Step1: Write the unbalanced reaction

For \(HCl(aq)+Ba(OH)_2(aq)\to\), the products are \(BaCl_2\) (aqueous) and \(H_2O\) (liquid). The un - balanced equation is \(HCl(aq)+Ba(OH)_2(aq)\to BaCl_2(aq)+H_2O(l)\).
For \(H_2SO_4(aq)+KOH(aq)\to\), the products are \(K_2SO_4\) (aqueous) and \(H_2O\) (liquid). The un - balanced equation is \(H_2SO_4(aq)+KOH(aq)\to K_2SO_4(aq)+H_2O(l)\).

Step2: Balance the equations

• For \(HCl(aq)+Ba(OH)_2(aq)\to BaCl_2(aq)+H_2O(l)\):
• Balance \(Cl\) atoms: There are 2 \(Cl\) atoms in \(BaCl_2\), so we put a coefficient of 2 in front of \(HCl\). The equation becomes \(2HCl(aq)+Ba(OH)_2(aq)\to BaCl_2(aq)+H_2O(l)\).
• Balance \(H\) and \(O\) atoms: On the left - hand side, we have \(2 + 2=4\) \(H\) atoms and 2 \(O\) atoms. On the right - hand side, in \(BaCl_2\) there are 0 \(H\) and 0 \(O\) (from \(BaCl_2\)), and in \(H_2O\) we have 2 \(H\) and 1 \(O\). After putting a coefficient of 2 in front of \(H_2O\), the balanced equation is \(2HCl(aq)+Ba(OH)_2(aq)=BaCl_2(aq)+2H_2O(l)\).
• For \(H_2SO_4(aq)+KOH(aq)\to K_2SO_4(aq)+H_2O(l)\):
• Balance \(K\) atoms: There are 2 \(K\) atoms in \(K_2SO_4\), so we put a coefficient of 2 in front of \(KOH\). The equation becomes \(H_2SO_4(aq)+2KOH(aq)\to K_2SO_4(aq)+H_2O(l)\).
• Balance \(H\) and \(O\) atoms: On the left - hand side, we have \(2+2 = 4\) \(H\) atoms and \(4 + 2=6\) \(O\) atoms. On the right - hand side, in \(K_2SO_4\) there are 0 \(H\) and 4 \(O\) (from \(K_2SO_4\)), and in \(H_2O\) we have 2 \(H\) and 1 \(O\). After putting a coefficient of 2 in front of \(H_2O\), the balanced equation is \(H_2SO_4(aq)+2KOH(aq)=K_2SO_4(aq)+2H_2O(l)\).

Answer:

• \(2HCl(aq)+Ba(OH)_2(aq)=BaCl_2(aq)+2H_2O(l)\)
• \(H_2SO_4(aq)+2KOH(aq)=K_2SO_4(aq)+2H_2O(l)\)