Question

having problems staying logged in or are you experiencing issues? please visit our troubleshooting section for solutions. an object has an acceleration of 6.0 m/s/s. if the net force acting upon this object were halved (i.e., one - half of the original net force), then its new acceleration would be ______ m/s/s. enter your answer directly into the field or use our built - in number pad. new acceleration (in m/s/s)

Explanation:

Step1: Recall Newton's second law

Newton's second law is \(F = ma\), where \(F\) is the net force, \(m\) is the mass, and \(a\) is the acceleration. Initially, \(F_1=m\times a_1\), and \(a_1 = 6.0\space m/s^2\).

Step2: Analyze the new - force situation

The new force \(F_2=\frac{1}{2}F_1\). Since the mass \(m\) of the object remains constant (assuming no change in the object's mass), and \(F_2=m\times a_2\). Substitute \(F_2=\frac{1}{2}F_1\) into \(F_2=m\times a_2\), we get \(\frac{1}{2}F_1=m\times a_2\). But \(F_1 = m\times a_1\), so \(\frac{1}{2}(m\times a_1)=m\times a_2\).

Step3: Solve for the new acceleration

Cancel out the mass \(m\) (since \(m
eq0\)) from both sides of the equation \(\frac{1}{2}(m\times a_1)=m\times a_2\). We get \(a_2=\frac{1}{2}a_1\).

Answer:

\(3.0\)