Question

the ground state electron configuration of a se atom is

incorrect, 3 attempts remaining

a

b

c

d

e

you identified the configuration of an as atom. se is in group 6a (16) but in the fourth period.

Explanation:

• Selenium (Se) has an atomic number of 34.
• The electron configuration is built by filling orbitals in the order \(1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p\).
• \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{4}\) follows the Aufbau principle (filling orbitals from lowest to highest energy).
• Option A misses the \(3d^{10}\) electrons. Option B has incorrect orbital \(4d\) (should be \(3d\)). Option D is for an atom with atomic number \(16\) (Sulfur). Option E has incorrect \(4p\) electron count (\(4p^{3}\) instead of \(4p^{4}\)).

Answer:

C. \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{4}\)