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the graph shows quadrilaterals cdef and rstu. is cdef congruent to rstu…

Question

the graph shows quadrilaterals cdef and rstu. is cdef congruent to rstu? justify your answer. yes, because a reflection across the y - axis maps cdef onto rstu. yes, because a rotation 90° clockwise around the origin maps cdef onto rstu. no, because \\( \overline { fc } \\) and \\( \overline { ur } \\) do not have the same length. no, because \\( \overline { de } \\) and \\( \overline { st } \\) do not have the same length.

Explanation:

Step1: Calculate the length of \( \overline{DE} \)

Use the distance formula \( d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2} \). For points \( D(9,-5) \) and \( E(6,-2) \), \( x_1 = 9,y_1=-5,x_2 = 6,y_2=-2 \).

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Step2: Calculate the length of \( \overline{ST} \)

For points \( S(-8,-5) \) and \( T(-6,-2) \), \( x_1=-8,y_1 = -5,x_2=-6,y_2=-2 \).

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Since \( 3\sqrt{2}
eq\sqrt{13} \), \( \overline{DE} \) and \( \overline{ST} \) do not have the same length. Congruent figures have all corresponding sides equal.

Answer:

No, because \( \overline{DE} \) and \( \overline{ST} \) do not have the same length.