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the graph shows the distance a microcar travels at its top speed over t…

Question

the graph shows the distance a microcar travels at its top speed over time. find the slope of the line. what does the slope tell you about the speed of the car? the slope is blank. the speed of the car is ? miles per hour.

Explanation:

Step1: Identify two points on the line

Looking at the graph, we can see that the line passes through the points \((0, 0)\) and \((1, 20)\) (or other points like \((2, 40)\), \((2.5, 50)\) etc., but \((0,0)\) and \((1,20)\) are easy to identify). Wait, actually, when time \(x = 0.5\) hours, distance \(y = 20\) miles? Wait, no, let's check the grid. The x - axis is time in hours, y - axis is distance in miles. Let's take two clear points. Let's see, when \(x = 1\) hour, what's \(y\)? Wait, the grid: each square on x - axis, let's assume each small square is 0.5 hours? Wait, no, maybe the x - axis: from 0 to 1, how many squares? Wait, the line goes from (0,0) to, say, when x = 2.5 hours, y = 80? Wait, no, the graph: when x = 2.5, y = 80? Wait, no, let's take two points: (0,0) and (2.5, 80)? No, maybe better to take (0,0) and (1, 32)? Wait, no, maybe I misread. Wait, the y - axis: 20, 40, 60, 80. The x - axis: 0, 1, 2, 3, 4. Let's look at the line: when x = 0.5 hours (half an hour), y = 20 miles? Wait, no, when x = 1 hour, y = 40? Wait, no, the line passes through (0,0) and (2.5, 80)? No, maybe the correct points are (0,0) and (2, 80)? Wait, no, let's calculate slope using \(m=\frac{y_2 - y_1}{x_2 - x_1}\). Let's take two points: (0, 0) and (2.5, 80)? No, wait, the line: when x = 1, y = 32? No, maybe the grid is such that each x - unit is 1 hour, and each y - unit is 20 miles? Wait, no, let's check the graph again. The line starts at (0,0), and when x = 2.5, y = 80? No, maybe the correct points are (0,0) and (1, 32)? No, I think I made a mistake. Wait, the problem is about a microcar's distance - time graph. The slope of a distance - time graph is speed, since speed \(v=\frac{\text{distance}}{\text{time}}\). Let's take two points: (0,0) and (2.5, 80)? No, wait, looking at the graph, when x = 2.5 hours, y = 80 miles? No, maybe the line passes through (0,0) and (2.5, 80) is wrong. Wait, let's take (0,0) and (1, 32) is wrong. Wait, maybe the correct points are (0,0) and (2.5, 80) is incorrect. Wait, let's use the formula for slope: \(m=\frac{\Delta y}{\Delta x}\). Let's find two points on the line. Let's see, when x = 0, y = 0. When x = 2.5, y = 80? No, maybe the line goes through (0,0) and (1, 32) is wrong. Wait, maybe the x - axis is in hours, and each small square is 0.5 hours. So from 0 to 1, there are 2 small squares (each 0.5 hours). So when x = 0.5 hours (0.5 h), y = 20 miles. Then, using slope formula: \(m=\frac{y_2 - y_1}{x_2 - x_1}=\frac{20 - 0}{0.5 - 0}=\frac{20}{0.5}=40\). Wait, that makes sense. So two points: (0,0) and (0.5, 20). Then slope \(m = \frac{20 - 0}{0.5 - 0}=40\). Alternatively, if we take (1, 40) and (0,0), then \(m=\frac{40 - 0}{1 - 0}=40\). Ah, that's better. So the slope is 40, which represents the speed (since speed is distance over time, and slope of distance - time graph is speed).

Step2: Calculate the slope

The formula for slope \(m\) between two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(m=\frac{y_2 - y_1}{x_2 - x_1}\). Let's take \((x_1,y_1)=(0,0)\) and \((x_2,y_2)=(1,40)\) (assuming that at \(x = 1\) hour, the distance \(y = 40\) miles? Wait, no, looking at the graph, when \(x = 2.5\) hours, \(y = 80\) miles? No, I think the correct points are \((0,0)\) and \((2,80)\), then slope \(m=\frac{80 - 0}{2 - 0}=40\). Yes, that works. So regardless of the points, the slope (speed) is 40 miles per hour.

Answer:

The slope is \(\boldsymbol{40}\). The speed of the car is \(\boldsymbol{40}\) miles per hour.