Question

graph the linear equation $y = \frac{1}{2}x - 2$. complete the table. \

$$\begin{tabular}{|c|c|} \\hline $x$ & $y$ \\\\ \\hline 0 & | \\\\ \\hline 2 & ? \\\\ \\hline \\end{tabular}$$

Explanation:

Step1: Find y when x=0

Substitute \( x = 0 \) into \( y=\frac{1}{2}x - 2 \).
\( y=\frac{1}{2}(0)-2 = -2 \).

Step2: Find y when x=2

Substitute \( x = 2 \) into \( y=\frac{1}{2}x - 2 \).
\( y=\frac{1}{2}(2)-2 = 1 - 2 = -1 \).

Answer:

For \( x = 0 \), \( y = -2 \); for \( x = 2 \), \( y = -1 \). So the completed table (row - by - row) has \( y \)-values \(-2\) (when \( x = 0 \)) and \(-1\) (when \( x = 2 \)).