Question

graph the image of trapezoid j k l m after a reflection over the line y = -x.

Explanation:

Step1: Find coordinates of original points

From the graph, we have \(J(5,1)\), \(K(5,5)\), \(L(6,10)\), \(M(6,0)\).

Step2: Apply reflection formula

The formula for reflection over the line \(y = -x\) is \((x,y)\to(-y,-x)\).

• For \(J(5,1)\): \((5,1)\to(-1,-5)\)
• For \(K(5,5)\): \((5,5)\to(-5,-5)\)
• For \(L(6,10)\): \((6,10)\to(-10,-6)\)
• For \(M(6,0)\): \((6,0)\to(0,-6)\)

Step3: Plot the new points

Plot the points \(J'(-1,-5)\), \(K'(-5,-5)\), \(L'(-10,-6)\), \(M'(0,-6)\) and connect them to form the reflected trapezoid.

Answer:

Plot the points \(J'(-1,-5)\), \(K'(-5,-5)\), \(L'(-10,-6)\), \(M'(0,-6)\) and connect them.