Question

graph the image of square j k l m after a translation 10 units left and 3 units down.

Explanation:

Step1: Find the coordinates of original points

• Point \(J(0,- 2)\), \(K(10,-2)\), \(L(10,8)\), \(M(0,8)\)

Step2: Apply the translation rule

• The translation rule for \(10\) units left (\(x\) - coordinate: \(x-10\)) and \(3\) units down (\(y\) - coordinate: \(y - 3\))
• For point \(J\): \(x=0-10=-10\), \(y=-2 - 3=-5\), new point \(J'(-10,-5)\)
• For point \(K\): \(x = 10-10=0\), \(y=-2-3=-5\), new point \(K'(0,-5)\)
• For point \(L\): \(x=10 - 10=0\), \(y=8-3 = 5\), new point \(L'(0,5)\)
• For point \(M\): \(x=0-10=-10\), \(y=8-3=5\), new point \(M'(-10,5)\)

Step3: Plot the new points

• Plot \(J'(-10,-5)\), \(K'(0,-5)\), \(L'(0,5)\), \(M'(-10,5)\) and connect them to form the translated square.

Answer:

Plot the points \(J'(-10,-5)\), \(K'(0,-5)\), \(L'(0,5)\), \(M'(-10,5)\) and connect them.