Question

graph the image of \\( \delta stu \\) after a translation 9 units right.

Explanation:

Step1: Find the coordinates of the original triangle's vertices

Assume the coordinates of \(S\) is \((-9,-6)\), \(T\) is \((-3,-6)\), and \(U\) is \((-9,-5)\) (by observing the graph).

Step2: Apply the translation rule

The rule for a translation \(9\) units right is \((x,y)\to(x + 9,y)\).
For \(S(-9,-6)\): \((-9+9,-6)=(0,-6)\).
For \(T(-3,-6)\): \((-3 + 9,-6)=(6,-6)\).
For \(U(-9,-5)\): \((-9+9,-5)=(0,-5)\).

Step3: Plot the new vertices

Plot the points \((0,-6)\), \((6,-6)\), and \((0,-5)\) on the coordinate plane and connect them to form the translated triangle \(\triangle S'T'U'\).

Answer:

Plot the points \((0,-6)\), \((6,-6)\), \((0,-5)\) and connect them.